Had an idea - looking for a math buff to tell me if it's possible?with today's technology.
paul at paulgraydon.co.uk
Fri May 20 19:34:59 UTC 2011
On 05/20/2011 08:53 AM, Brett Frankenberger wrote:
> On Fri, May 20, 2011 at 06:46:45PM +0000, Eu-Ming Lee wrote:
>> To do this, you only need 2 numbers: the nth digit of pi and the number of
>> Simply convert your message into a single extremely long integer. Somewhere,
>> in the digits of pi, you will find a matching series of digits the same as
>> your integer!
>> Decompressing the number is relatively easy after some sort-of recent
>> advances in our understanding of pi.
>> Finding out what those 2 numbers are--- well, we still have a ways to go
>> on that.
> Even if those problems were solved, you'd need (on average) just as
> many bits to represent which digit of pi to start with as you'd need to
> represent the original message.
> -- Brett
Not quite sure I follow that. "Start at position xyz, carry on for 10000
bits" shouldn't be as long as telling it all 10000 bits?
More information about the NANOG