IPv6 Routing table will be bloated?

Tue Oct 26 22:00:51 UTC 2010

Yes indeed, but you don't have to justify much if you only ask for the minimum, if you want more you need to ask...

Also, and this I like less, your membership is calculated from the number of IPs you have... I think in short $$=max(1180x1.3(log2(Addresses in /32)-8),Feev6 = 1180x1.3(log2(Addresses in /56)-22)

http://www.apnic.net/services/apply-for-resources/check-your-eligibility/check-ipv6
http://www.apnic.net/services/become-a-member/how-much-does-it-cost

----- Original Message -----
From: "Randy Carpenter" <rcarpen at network1.net>
To: "Franck Martin" <franck at genius.com>
Cc: nanog at nanog.org, "Nick Hilliard" <nick at foobar.org>
Sent: Wednesday, 27 October, 2010 10:48:13 AM
Subject: Re: IPv6 Routing table will be bloated?

It would be nice as a start, but does not really take into consideration future expansion needs.

I would think that you could draw some parallels, though.

Something like:

v4 /16 ~ v6 /32
v4 /12 ~ v6 /28
v4 /8 ~ v6 /24

I know it we don't want to equate v4 and v6, but it may help as a guideline for the size of the customer base.