How do you (not how do I) calculate 95th percentile?

Wed Feb 22 22:10:11 UTC 2006

Doh! You are 100% correct.

I didn't take into account the fact that the counters are if(In|Out) 
*Octets* and NOT if(in/Out)*Bits*.

The point is that 64-bit counters are not likely to roll :-)

Warren

On Feb 22, 2006, at 12:24 PM, Alex Rubenstein wrote:

>
>
> (I did this fast, and, who knows; I could be off my an order or two  
> of magnitude)
>
>> Most people are using 64 bit counters. This avoids the wrapping  
>> problem (assuming you don't have 100GE and poll more then once  
>> every 5 years :-)).
>
> 2^64 is 18,446,744,073,709,551,616 bytes.
>
> 100 GE (100,000,000,000 bits/sec) is 12,500,000,000 bytes/sec.
>
> It would take 1,475,739,525 seconds, or 46.79 years for a counter  
> wrap.
>
>
> -- 
> Alex Rubenstein, AR97, K2AHR, alex at nac.net, latency, Al Reuben
> Net Access Corporation, 800-NET-ME-36, http://www.nac.net
>
>