Fwd: SlashDot: "Comcast Gunning for NAT Users"

Todd Suiter todd at s4r.com
Thu Jan 31 23:21:32 UTC 2002



	Indeed, I DO have a a linksys for just that reason, in fact its
a 1 wan/1 lan version...'Course, its plugged into a switch, that has
an airport attached as well but...

	I have been, and am constantly probed for just about everything under
the, er, sun. Considering the amount of people out there who have less
than a full allotment of clue for these types of things, the larger issue
is the OS vendors should probably make an effort to not turn on every
less-than-secure service out of the box on a default install. But thats
probably off topic...

	Having some sort of firewall is a good start, though not
a complete solution. The comcasts of the world are only going to hurt
themselves more if they continue to make a huge stink out of this. (Yes,
I know a fw!=NAT, but do you think the vendor will make that distinction?)

toddler

(ps yes, at times I think using a computer on the internet should require a license)

On Thu, 31 Jan 2002, M. David Leonard wrote:

>
>
> 	You know, if I had a cable modem I would have some sort of
> firewall router just to preserve my peace of mind.  I might even run NAT
> on the LAN side.  So the question is this:  can a customer use a firewall
> for *one* computer?  If so, how can the cableco determine whether there
> is a single computer or two computers or more behind a firewall?  I
> really don't think they can except in cases of egregious abuse.
>
>
> 					David Leonard
> 					ShaysNet
>
>
> On Thu, 31 Jan 2002, Eric A. Hall wrote:
>
> >
> >
> > "Eric A. Hall" wrote:
> >
> > > If you use too much bandwidth, they will [] drop your service.
> >
> > ps--the original message sounds like they have gone beyond hunting down
> > the people running warez servers and the like, and have gone into an
> > agressive mode of pursuing anybody with a NAT regardless of their
> > utilization. I have no idea if that is true. I don't think it would be a
> > smart move on their part but that probably doesn't enter the equation.
> >
> > --
> > Eric A. Hall                                        http://www.ehsco.com/
> > Internet Core Protocols          http://www.oreilly.com/catalog/coreprot/
> >
>




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